4(3x+2)-5(6x-1)=2(x-8)-6(7x-4)+4x

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Solution for 4(3x+2)-5(6x-1)=2(x-8)-6(7x-4)+4x equation:



4(3x+2)-5(6x-1)=2(x-8)-6(7x-4)+4x
We move all terms to the left:
4(3x+2)-5(6x-1)-(2(x-8)-6(7x-4)+4x)=0
We multiply parentheses
12x-30x-(2(x-8)-6(7x-4)+4x)+8+5=0
We calculate terms in parentheses: -(2(x-8)-6(7x-4)+4x), so:
2(x-8)-6(7x-4)+4x
We add all the numbers together, and all the variables
4x+2(x-8)-6(7x-4)
We multiply parentheses
4x+2x-42x-16+24
We add all the numbers together, and all the variables
-36x+8
Back to the equation:
-(-36x+8)
We add all the numbers together, and all the variables
-18x-(-36x+8)+13=0
We get rid of parentheses
-18x+36x-8+13=0
We add all the numbers together, and all the variables
18x+5=0
We move all terms containing x to the left, all other terms to the right
18x=-5
x=-5/18
x=-5/18

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