4(3x+2)-5=6(2x-3)+21

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Solution for 4(3x+2)-5=6(2x-3)+21 equation: 



4(3x+2)-5=6(2x-3)+21

We move all terms to the left:

4(3x+2)-5-(6(2x-3)+21)=0

We multiply parentheses

12x-(6(2x-3)+21)+8-5=0



We calculate terms in parentheses: -(6(2x-3)+21), so:

6(2x-3)+21

We multiply parentheses

12x-18+21

We add all the numbers together, and all the variables

12x+3

Back to the equation:

-(12x+3)



We add all the numbers together, and all the variables

12x-(12x+3)+3=0

We get rid of parentheses

12x-12x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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