4(3x+2)-7(x+1)=3(x-1)

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Solution for 4(3x+2)-7(x+1)=3(x-1) equation: 



4(3x+2)-7(x+1)=3(x-1)

We move all terms to the left:

4(3x+2)-7(x+1)-(3(x-1))=0

We multiply parentheses

12x-7x-(3(x-1))+8-7=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

5x-(3x-3)+1=0

We get rid of parentheses

5x-3x+3+1=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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