4(3x+2)-7(x-2)=7

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Solution for 4(3x+2)-7(x-2)=7 equation: 



4(3x+2)-7(x-2)=7

We move all terms to the left:

4(3x+2)-7(x-2)-(7)=0

We multiply parentheses

12x-7x+8+14-7=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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