4(3x+2)-x=8x+(-8)

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Solution for 4(3x+2)-x=8x+(-8) equation:



4(3x+2)-x=8x+(-8)
We move all terms to the left:
4(3x+2)-x-(8x+(-8))=0
We add all the numbers together, and all the variables
-1x+4(3x+2)-(8x+(-8))=0
We multiply parentheses
-1x+12x-(8x+(-8))+8=0
We calculate terms in parentheses: -(8x+(-8)), so:
8x+(-8)
We add all the numbers together, and all the variables
8x-8
Back to the equation:
-(8x-8)
We add all the numbers together, and all the variables
11x-(8x-8)+8=0
We get rid of parentheses
11x-8x+8+8=0
We add all the numbers together, and all the variables
3x+16=0
We move all terms containing x to the left, all other terms to the right
3x=-16
x=-16/3
x=-5+1/3

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