4(3x+20)=12+80

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Solution for 4(3x+20)=12+80 equation: 



4(3x+20)=12+80

We move all terms to the left:

4(3x+20)-(12+80)=0

We add all the numbers together, and all the variables

4(3x+20)-92=0

We multiply parentheses

12x+80-92=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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