4(3x+3)(x-1)=0

Solution for 4(3x+3)(x-1)=0 equation:

Simplifying
4(3x + 3)(x + -1) = 0

Reorder the terms:
4(3 + 3x)(x + -1) = 0

Reorder the terms:
4(3 + 3x)(-1 + x) = 0

Multiply (3 + 3x) * (-1 + x)
4(3(-1 + x) + 3x * (-1 + x)) = 0
4((-1 * 3 + x * 3) + 3x * (-1 + x)) = 0
4((-3 + 3x) + 3x * (-1 + x)) = 0
4(-3 + 3x + (-1 * 3x + x * 3x)) = 0
4(-3 + 3x + (-3x + 3x2)) = 0

Combine like terms: 3x + -3x = 0
4(-3 + 0 + 3x2) = 0
4(-3 + 3x2) = 0
(-3 * 4 + 3x2 * 4) = 0
(-12 + 12x2) = 0

Solving
-12 + 12x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 12x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 12x2 = 0 + 12
12x2 = 0 + 12

Combine like terms: 0 + 12 = 12
12x2 = 12

Divide each side by '12'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}