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4(3x+3)+x=2(10x+6)
We move all terms to the left:
4(3x+3)+x-(2(10x+6))=0
We add all the numbers together, and all the variables
x+4(3x+3)-(2(10x+6))=0
We multiply parentheses
x+12x-(2(10x+6))+12=0
We calculate terms in parentheses: -(2(10x+6)), so:We add all the numbers together, and all the variables
2(10x+6)
We multiply parentheses
20x+12
Back to the equation:
-(20x+12)
13x-(20x+12)+12=0
We get rid of parentheses
13x-20x-12+12=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
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