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4(3x+3)=-3(2x-5)+5x
We move all terms to the left:
4(3x+3)-(-3(2x-5)+5x)=0
We multiply parentheses
12x-(-3(2x-5)+5x)+12=0
We calculate terms in parentheses: -(-3(2x-5)+5x), so:We get rid of parentheses
-3(2x-5)+5x
We add all the numbers together, and all the variables
5x-3(2x-5)
We multiply parentheses
5x-6x+15
We add all the numbers together, and all the variables
-1x+15
Back to the equation:
-(-1x+15)
12x+1x-15+12=0
We add all the numbers together, and all the variables
13x-3=0
We move all terms containing x to the left, all other terms to the right
13x=3
x=3/13
x=3/13
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