4(3x+3)=16x+11-4X+1

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Solution for 4(3x+3)=16x+11-4X+1 equation: 



4(3x+3)=16x+11-4x+1

We move all terms to the left:

4(3x+3)-(16x+11-4x+1)=0

We add all the numbers together, and all the variables

4(3x+3)-(12x+12)=0

We multiply parentheses

12x-(12x+12)+12=0

We get rid of parentheses

12x-12x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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