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4(3x+3)=16x+11-4x+1
We move all terms to the left:
4(3x+3)-(16x+11-4x+1)=0
We add all the numbers together, and all the variables
4(3x+3)-(12x+12)=0
We multiply parentheses
12x-(12x+12)+12=0
We get rid of parentheses
12x-12x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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