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4(3x+3)=3(2x+2)
We move all terms to the left:
4(3x+3)-(3(2x+2))=0
We multiply parentheses
12x-(3(2x+2))+12=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
12x-6x-6+12=0
We add all the numbers together, and all the variables
6x+6=0
We move all terms containing x to the left, all other terms to the right
6x=-6
x=-6/6
x=-1
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