4(3x+3)=68

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Solution for 4(3x+3)=68 equation: 



4(3x+3)=68

We move all terms to the left:

4(3x+3)-(68)=0

We multiply parentheses

12x+12-68=0

We add all the numbers together, and all the variables

12x-56=0

We move all terms containing x to the left, all other terms to the right

12x=56

x=56/12

x=4+2/3

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