4(3x+4)+41=17x+13-5x+44

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Solution for 4(3x+4)+41=17x+13-5x+44 equation: 


Simplifying
4(3x + 4) + 41 = 17x + 13 + -5x + 44

Reorder the terms:
4(4 + 3x) + 41 = 17x + 13 + -5x + 44
(4 * 4 + 3x * 4) + 41 = 17x + 13 + -5x + 44
(16 + 12x) + 41 = 17x + 13 + -5x + 44

Reorder the terms:
16 + 41 + 12x = 17x + 13 + -5x + 44

Combine like terms: 16 + 41 = 57
57 + 12x = 17x + 13 + -5x + 44

Reorder the terms:
57 + 12x = 13 + 44 + 17x + -5x

Combine like terms: 13 + 44 = 57
57 + 12x = 57 + 17x + -5x

Combine like terms: 17x + -5x = 12x
57 + 12x = 57 + 12x

Add '-57' to each side of the equation.
57 + -57 + 12x = 57 + -57 + 12x

Combine like terms: 57 + -57 = 0
0 + 12x = 57 + -57 + 12x
12x = 57 + -57 + 12x

Combine like terms: 57 + -57 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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