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4(3x+40)=2(x+20)
We move all terms to the left:
4(3x+40)-(2(x+20))=0
We multiply parentheses
12x-(2(x+20))+160=0
We calculate terms in parentheses: -(2(x+20)), so:We get rid of parentheses
2(x+20)
We multiply parentheses
2x+40
Back to the equation:
-(2x+40)
12x-2x-40+160=0
We add all the numbers together, and all the variables
10x+120=0
We move all terms containing x to the left, all other terms to the right
10x=-120
x=-120/10
x=-12
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