4(3x+5)+21=3(2x-5)+11

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Solution for 4(3x+5)+21=3(2x-5)+11 equation: 



4(3x+5)+21=3(2x-5)+11

We move all terms to the left:

4(3x+5)+21-(3(2x-5)+11)=0

We multiply parentheses

12x-(3(2x-5)+11)+20+21=0



We calculate terms in parentheses: -(3(2x-5)+11), so:

3(2x-5)+11

We multiply parentheses

6x-15+11

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

12x-(6x-4)+41=0

We get rid of parentheses

12x-6x+4+41=0

We add all the numbers together, and all the variables

6x+45=0

We move all terms containing x to the left, all other terms to the right

6x=-45

x=-45/6

x=-7+1/2

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