4(3x+5)-28=10x-2

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Solution for 4(3x+5)-28=10x-2 equation: 



4(3x+5)-28=10x-2

We move all terms to the left:

4(3x+5)-28-(10x-2)=0

We multiply parentheses

12x-(10x-2)+20-28=0

We get rid of parentheses

12x-10x+2+20-28=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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