4(3x+5)-6(3x-5)=12x+3(4x-7)

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Solution for 4(3x+5)-6(3x-5)=12x+3(4x-7) equation: 



4(3x+5)-6(3x-5)=12x+3(4x-7)

We move all terms to the left:

4(3x+5)-6(3x-5)-(12x+3(4x-7))=0

We multiply parentheses

12x-18x-(12x+3(4x-7))+20+30=0



We calculate terms in parentheses: -(12x+3(4x-7)), so:

12x+3(4x-7)

We multiply parentheses

12x+12x-21

We add all the numbers together, and all the variables

24x-21

Back to the equation:

-(24x-21)



We add all the numbers together, and all the variables

-6x-(24x-21)+50=0

We get rid of parentheses

-6x-24x+21+50=0

We add all the numbers together, and all the variables

-30x+71=0

We move all terms containing x to the left, all other terms to the right

-30x=-71

x=-71/-30

x=2+11/30

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