4(3x+5)-6(4x-7)=11x+(4x-8)

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Solution for 4(3x+5)-6(4x-7)=11x+(4x-8) equation: 



4(3x+5)-6(4x-7)=11x+(4x-8)

We move all terms to the left:

4(3x+5)-6(4x-7)-(11x+(4x-8))=0

We multiply parentheses

12x-24x-(11x+(4x-8))+20+42=0



We calculate terms in parentheses: -(11x+(4x-8)), so:

11x+(4x-8)

We get rid of parentheses

11x+4x-8

We add all the numbers together, and all the variables

15x-8

Back to the equation:

-(15x-8)



We add all the numbers together, and all the variables

-12x-(15x-8)+62=0

We get rid of parentheses

-12x-15x+8+62=0

We add all the numbers together, and all the variables

-27x+70=0

We move all terms containing x to the left, all other terms to the right

-27x=-70

x=-70/-27

x=2+16/27

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