4(3x+5)-6(4x-7)=11x+3(4x-8)

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Solution for 4(3x+5)-6(4x-7)=11x+3(4x-8) equation: 



4(3x+5)-6(4x-7)=11x+3(4x-8)

We move all terms to the left:

4(3x+5)-6(4x-7)-(11x+3(4x-8))=0

We multiply parentheses

12x-24x-(11x+3(4x-8))+20+42=0



We calculate terms in parentheses: -(11x+3(4x-8)), so:

11x+3(4x-8)

We multiply parentheses

11x+12x-24

We add all the numbers together, and all the variables

23x-24

Back to the equation:

-(23x-24)



We add all the numbers together, and all the variables

-12x-(23x-24)+62=0

We get rid of parentheses

-12x-23x+24+62=0

We add all the numbers together, and all the variables

-35x+86=0

We move all terms containing x to the left, all other terms to the right

-35x=-86

x=-86/-35

x=2+16/35

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