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4(3x+5)=(9x-5)
We move all terms to the left:
4(3x+5)-((9x-5))=0
We multiply parentheses
12x-((9x-5))+20=0
We calculate terms in parentheses: -((9x-5)), so:We get rid of parentheses
(9x-5)
We get rid of parentheses
9x-5
Back to the equation:
-(9x-5)
12x-9x+5+20=0
We add all the numbers together, and all the variables
3x+25=0
We move all terms containing x to the left, all other terms to the right
3x=-25
x=-25/3
x=-8+1/3
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