4(3x+5)=11(x+1)

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Solution for 4(3x+5)=11(x+1) equation: 



4(3x+5)=11(x+1)

We move all terms to the left:

4(3x+5)-(11(x+1))=0

We multiply parentheses

12x-(11(x+1))+20=0



We calculate terms in parentheses: -(11(x+1)), so:

11(x+1)

We multiply parentheses

11x+11

Back to the equation:

-(11x+11)



We get rid of parentheses

12x-11x-11+20=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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