4(3x+5)=16(2x+1)

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Solution for 4(3x+5)=16(2x+1) equation: 



4(3x+5)=16(2x+1)

We move all terms to the left:

4(3x+5)-(16(2x+1))=0

We multiply parentheses

12x-(16(2x+1))+20=0



We calculate terms in parentheses: -(16(2x+1)), so:

16(2x+1)

We multiply parentheses

32x+16

Back to the equation:

-(32x+16)



We get rid of parentheses

12x-32x-16+20=0

We add all the numbers together, and all the variables

-20x+4=0

We move all terms containing x to the left, all other terms to the right

-20x=-4

x=-4/-20

x=1/5

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