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4(3x+5)=19x+5-7x+15
We move all terms to the left:
4(3x+5)-(19x+5-7x+15)=0
We add all the numbers together, and all the variables
4(3x+5)-(12x+20)=0
We multiply parentheses
12x-(12x+20)+20=0
We get rid of parentheses
12x-12x-20+20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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