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4(3x+5)=2(3x+34)
We move all terms to the left:
4(3x+5)-(2(3x+34))=0
We multiply parentheses
12x-(2(3x+34))+20=0
We calculate terms in parentheses: -(2(3x+34)), so:We get rid of parentheses
2(3x+34)
We multiply parentheses
6x+68
Back to the equation:
-(6x+68)
12x-6x-68+20=0
We add all the numbers together, and all the variables
6x-48=0
We move all terms containing x to the left, all other terms to the right
6x=48
x=48/6
x=8
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