4(3x+5+-4x)=3(3-4x)+8

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Solution for 4(3x+5+-4x)=3(3-4x)+8 equation: 



4(3x+5+-4x)=3(3-4x)+8

We move all terms to the left:

4(3x+5+-4x)-(3(3-4x)+8)=0

We add all the numbers together, and all the variables

4(-1x)-(3(-4x+3)+8)=0

We multiply parentheses

-4x-(3(-4x+3)+8)=0



We calculate terms in parentheses: -(3(-4x+3)+8), so:

3(-4x+3)+8

We multiply parentheses

-12x+9+8

We add all the numbers together, and all the variables

-12x+17

Back to the equation:

-(-12x+17)



We get rid of parentheses

-4x+12x-17=0

We add all the numbers together, and all the variables

8x-17=0

We move all terms containing x to the left, all other terms to the right

8x=17

x=17/8

x=2+1/8

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