4(3x+6)+2(2x+2)+3=16x+31

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Solution for 4(3x+6)+2(2x+2)+3=16x+31 equation: 



4(3x+6)+2(2x+2)+3=16x+31

We move all terms to the left:

4(3x+6)+2(2x+2)+3-(16x+31)=0

We multiply parentheses

12x+4x-(16x+31)+24+4+3=0

We get rid of parentheses

12x+4x-16x-31+24+4+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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