4(3x+6)/6=7(2x-8)/3+4

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Solution for 4(3x+6)/6=7(2x-8)/3+4 equation:



4(3x+6)/6=7(2x-8)/3+4
We move all terms to the left:
4(3x+6)/6-(7(2x-8)/3+4)=0
We calculate fractions
(36x+72)/()+(-(7(2x-8)*6)/()=0
We calculate terms in parentheses: +(-(7(2x-8)*6)/(), so:
-(7(2x-8)*6)/(
We multiply all the terms by the denominator
-(7(2x-8)*6)
We calculate terms in parentheses: -(7(2x-8)*6), so:
7(2x-8)*6
We multiply parentheses
84x-336
Back to the equation:
-(84x-336)
We get rid of parentheses
-84x+336
Back to the equation:
+(-84x+336)
We get rid of parentheses
(36x+72)/()-84x+336=0
We multiply all the terms by the denominator
(36x+72)-84x*()+336*()=0
We add all the numbers together, and all the variables
(36x+72)-84x*()=0
We get rid of parentheses
36x-84x*()+72=0
We move all terms containing x to the left, all other terms to the right
36x-84x*()=-72

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