4(3x+7)=64+4x

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Solution for 4(3x+7)=64+4x equation: 



4(3x+7)=64+4x

We move all terms to the left:

4(3x+7)-(64+4x)=0

We add all the numbers together, and all the variables

4(3x+7)-(4x+64)=0

We multiply parentheses

12x-(4x+64)+28=0

We get rid of parentheses

12x-4x-64+28=0

We add all the numbers together, and all the variables

8x-36=0

We move all terms containing x to the left, all other terms to the right

8x=36

x=36/8

x=4+1/2

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