4(3x+x)+7-5x=8+(-5)(5x-6x)-23

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Solution for 4(3x+x)+7-5x=8+(-5)(5x-6x)-23 equation:



4(3x+x)+7-5x=8+(-5)(5x-6x)-23
We move all terms to the left:
4(3x+x)+7-5x-(8+(-5)(5x-6x)-23)=0
We add all the numbers together, and all the variables
4(+4x)-5x-(8+(-5)(-1x)-23)+7=0
We add all the numbers together, and all the variables
-5x+4(+4x)-(8+(-5)(-1x)-23)+7=0
We multiply parentheses
-5x+16x-(8+(-5)(-1x)-23)+7=0
We multiply parentheses ..
-5x+16x-(8+(+5x)-23)+7=0
We calculate terms in parentheses: -(8+(+5x)-23), so:
8+(+5x)-23
determiningTheFunctionDomain (+5x)+8-23
We add all the numbers together, and all the variables
(+5x)-15
We get rid of parentheses
5x-15
Back to the equation:
-(5x-15)
We add all the numbers together, and all the variables
11x-(5x-15)+7=0
We get rid of parentheses
11x-5x+15+7=0
We add all the numbers together, and all the variables
6x+22=0
We move all terms containing x to the left, all other terms to the right
6x=-22
x=-22/6
x=-3+2/3

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