4(3x-1)+22=6(2x+3)

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Solution for 4(3x-1)+22=6(2x+3) equation:



4(3x-1)+22=6(2x+3)
We move all terms to the left:
4(3x-1)+22-(6(2x+3))=0
We multiply parentheses
12x-(6(2x+3))-4+22=0
We calculate terms in parentheses: -(6(2x+3)), so:
6(2x+3)
We multiply parentheses
12x+18
Back to the equation:
-(12x+18)
We add all the numbers together, and all the variables
12x-(12x+18)+18=0
We get rid of parentheses
12x-12x-18+18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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