4(3x-1)+3(4x-1)=12(2x-2)

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Solution for 4(3x-1)+3(4x-1)=12(2x-2) equation:


Simplifying
4(3x + -1) + 3(4x + -1) = 12(2x + -2)

Reorder the terms:
4(-1 + 3x) + 3(4x + -1) = 12(2x + -2)
(-1 * 4 + 3x * 4) + 3(4x + -1) = 12(2x + -2)
(-4 + 12x) + 3(4x + -1) = 12(2x + -2)

Reorder the terms:
-4 + 12x + 3(-1 + 4x) = 12(2x + -2)
-4 + 12x + (-1 * 3 + 4x * 3) = 12(2x + -2)
-4 + 12x + (-3 + 12x) = 12(2x + -2)

Reorder the terms:
-4 + -3 + 12x + 12x = 12(2x + -2)

Combine like terms: -4 + -3 = -7
-7 + 12x + 12x = 12(2x + -2)

Combine like terms: 12x + 12x = 24x
-7 + 24x = 12(2x + -2)

Reorder the terms:
-7 + 24x = 12(-2 + 2x)
-7 + 24x = (-2 * 12 + 2x * 12)
-7 + 24x = (-24 + 24x)

Add '-24x' to each side of the equation.
-7 + 24x + -24x = -24 + 24x + -24x

Combine like terms: 24x + -24x = 0
-7 + 0 = -24 + 24x + -24x
-7 = -24 + 24x + -24x

Combine like terms: 24x + -24x = 0
-7 = -24 + 0
-7 = -24

Solving
-7 = -24

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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