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4(3x-1)+5x=2(x-3)
We move all terms to the left:
4(3x-1)+5x-(2(x-3))=0
We add all the numbers together, and all the variables
5x+4(3x-1)-(2(x-3))=0
We multiply parentheses
5x+12x-(2(x-3))-4=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
17x-(2x-6)-4=0
We get rid of parentheses
17x-2x+6-4=0
We add all the numbers together, and all the variables
15x+2=0
We move all terms containing x to the left, all other terms to the right
15x=-2
x=-2/15
x=-2/15
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