4(3x-1)+76=2(4-2x)

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Solution for 4(3x-1)+76=2(4-2x) equation: 



4(3x-1)+76=2(4-2x)

We move all terms to the left:

4(3x-1)+76-(2(4-2x))=0

We add all the numbers together, and all the variables

4(3x-1)-(2(-2x+4))+76=0

We multiply parentheses

12x-(2(-2x+4))-4+76=0



We calculate terms in parentheses: -(2(-2x+4)), so:

2(-2x+4)

We multiply parentheses

-4x+8

Back to the equation:

-(-4x+8)



We add all the numbers together, and all the variables

12x-(-4x+8)+72=0

We get rid of parentheses

12x+4x-8+72=0

We add all the numbers together, and all the variables

16x+64=0

We move all terms containing x to the left, all other terms to the right

16x=-64

x=-64/16

x=-4

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