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4(3x-1)-5=2(x+4)
We move all terms to the left:
4(3x-1)-5-(2(x+4))=0
We multiply parentheses
12x-(2(x+4))-4-5=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
12x-(2x+8)-9=0
We get rid of parentheses
12x-2x-8-9=0
We add all the numbers together, and all the variables
10x-17=0
We move all terms containing x to the left, all other terms to the right
10x=17
x=17/10
x=1+7/10
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