4(3x-1)=11x-3x(x-4)

Solution for 4(3x-1)=11x-3x(x-4) equation:

4(3x-1)=11x-3x(x-4)

We move all terms to the left:

4(3x-1)-(11x-3x(x-4))=0

We multiply parentheses

12x-(11x-3x(x-4))-4=0


We calculate terms in parentheses: -(11x-3x(x-4)), so:

11x-3x(x-4)

We multiply parentheses

-3x^2+11x+12x

We add all the numbers together, and all the variables

-3x^2+23x

Back to the equation:

-(-3x^2+23x)


We get rid of parentheses

3x^2-23x+12x-4=0

We add all the numbers together, and all the variables

3x^2-11x-4=0

a = 3; b = -11; c = -4;
Δ = b2-4ac
Δ = -112-4·3·(-4)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-13}{2*3}=\frac{-2}{6}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+13}{2*3}=\frac{24}{6}
=4
$