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4(3x-1)=2(x+5)
We move all terms to the left:
4(3x-1)-(2(x+5))=0
We multiply parentheses
12x-(2(x+5))-4=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
12x-2x-10-4=0
We add all the numbers together, and all the variables
10x-14=0
We move all terms containing x to the left, all other terms to the right
10x=14
x=14/10
x=1+2/5
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