4(3x-1)=40+3x

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Solution for 4(3x-1)=40+3x equation: 



4(3x-1)=40+3x

We move all terms to the left:

4(3x-1)-(40+3x)=0

We add all the numbers together, and all the variables

4(3x-1)-(3x+40)=0

We multiply parentheses

12x-(3x+40)-4=0

We get rid of parentheses

12x-3x-40-4=0

We add all the numbers together, and all the variables

9x-44=0

We move all terms containing x to the left, all other terms to the right

9x=44

x=44/9

x=4+8/9

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