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4(3x-1)=5(2+x)
We move all terms to the left:
4(3x-1)-(5(2+x))=0
We add all the numbers together, and all the variables
4(3x-1)-(5(x+2))=0
We multiply parentheses
12x-(5(x+2))-4=0
We calculate terms in parentheses: -(5(x+2)), so:We get rid of parentheses
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
12x-5x-10-4=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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