4(3x-1)=68

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Solution for 4(3x-1)=68 equation: 



4(3x-1)=68

We move all terms to the left:

4(3x-1)-(68)=0

We multiply parentheses

12x-4-68=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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