4(3x-10)+3(5x+12)=212

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Solution for 4(3x-10)+3(5x+12)=212 equation: 



4(3x-10)+3(5x+12)=212

We move all terms to the left:

4(3x-10)+3(5x+12)-(212)=0

We multiply parentheses

12x+15x-40+36-212=0

We add all the numbers together, and all the variables

27x-216=0

We move all terms containing x to the left, all other terms to the right

27x=216

x=216/27

x=8

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