4(3x-15)=6(3x-27)

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Solution for 4(3x-15)=6(3x-27) equation: 



4(3x-15)=6(3x-27)

We move all terms to the left:

4(3x-15)-(6(3x-27))=0

We multiply parentheses

12x-(6(3x-27))-60=0



We calculate terms in parentheses: -(6(3x-27)), so:

6(3x-27)

We multiply parentheses

18x-162

Back to the equation:

-(18x-162)



We get rid of parentheses

12x-18x+162-60=0

We add all the numbers together, and all the variables

-6x+102=0

We move all terms containing x to the left, all other terms to the right

-6x=-102

x=-102/-6

x=+17

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