4(3x-2)+15=19

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Solution for 4(3x-2)+15=19 equation: 



4(3x-2)+15=19

We move all terms to the left:

4(3x-2)+15-(19)=0

We add all the numbers together, and all the variables

4(3x-2)-4=0

We multiply parentheses

12x-8-4=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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