4(3x-2)+18=2(6x+5)

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Solution for 4(3x-2)+18=2(6x+5) equation: 



4(3x-2)+18=2(6x+5)

We move all terms to the left:

4(3x-2)+18-(2(6x+5))=0

We multiply parentheses

12x-(2(6x+5))-8+18=0



We calculate terms in parentheses: -(2(6x+5)), so:

2(6x+5)

We multiply parentheses

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

12x-(12x+10)+10=0

We get rid of parentheses

12x-12x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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