4(3x-2)+2(x+8)-(4x-4)=0

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Solution for 4(3x-2)+2(x+8)-(4x-4)=0 equation: 



4(3x-2)+2(x+8)-(4x-4)=0

We multiply parentheses

12x+2x-(4x-4)-8+16=0

We get rid of parentheses

12x+2x-4x+4-8+16=0

We add all the numbers together, and all the variables

10x+12=0

We move all terms containing x to the left, all other terms to the right

10x=-12

x=-12/10

x=-1+1/5

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