4(3x-2)+7=6x+11

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Solution for 4(3x-2)+7=6x+11 equation:



4(3x-2)+7=6x+11
We move all terms to the left:
4(3x-2)+7-(6x+11)=0
We multiply parentheses
12x-(6x+11)-8+7=0
We get rid of parentheses
12x-6x-11-8+7=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2

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