4(3x-2)+8(x=1)=100

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Solution for 4(3x-2)+8(x=1)=100 equation:



4(3x-2)+8(x=1)=100
We move all terms to the left:
4(3x-2)+8(x-(1))=0
We multiply parentheses
12x+8x-8-8=0
We add all the numbers together, and all the variables
20x-16=0
We move all terms containing x to the left, all other terms to the right
20x=16
x=16/20
x=4/5

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