4(3x-2)-2=4(x-3)+42

Solution for 4(3x-2)-2=4(x-3)+42 equation:

4(3x-2)-2=4(x-3)+42

We move all terms to the left:

4(3x-2)-2-(4(x-3)+42)=0

We multiply parentheses

12x-(4(x-3)+42)-8-2=0


We calculate terms in parentheses: -(4(x-3)+42), so:

4(x-3)+42

We multiply parentheses

4x-12+42

We add all the numbers together, and all the variables

4x+30

Back to the equation:

-(4x+30)


We add all the numbers together, and all the variables

12x-(4x+30)-10=0

We get rid of parentheses

12x-4x-30-10=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5