4(3x-2)-3(2x+5)=8(2x+5)+7

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Solution for 4(3x-2)-3(2x+5)=8(2x+5)+7 equation: 



4(3x-2)-3(2x+5)=8(2x+5)+7

We move all terms to the left:

4(3x-2)-3(2x+5)-(8(2x+5)+7)=0

We multiply parentheses

12x-6x-(8(2x+5)+7)-8-15=0



We calculate terms in parentheses: -(8(2x+5)+7), so:

8(2x+5)+7

We multiply parentheses

16x+40+7

We add all the numbers together, and all the variables

16x+47

Back to the equation:

-(16x+47)



We add all the numbers together, and all the variables

6x-(16x+47)-23=0

We get rid of parentheses

6x-16x-47-23=0

We add all the numbers together, and all the variables

-10x-70=0

We move all terms containing x to the left, all other terms to the right

-10x=70

x=70/-10

x=-7

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