4(3x-2)-3(x-4)=7x+10

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Solution for 4(3x-2)-3(x-4)=7x+10 equation: 



4(3x-2)-3(x-4)=7x+10

We move all terms to the left:

4(3x-2)-3(x-4)-(7x+10)=0

We multiply parentheses

12x-3x-(7x+10)-8+12=0

We get rid of parentheses

12x-3x-7x-10-8+12=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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