4(3x-2)-4=4(x-4)+44

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Solution for 4(3x-2)-4=4(x-4)+44 equation: 



4(3x-2)-4=4(x-4)+44

We move all terms to the left:

4(3x-2)-4-(4(x-4)+44)=0

We multiply parentheses

12x-(4(x-4)+44)-8-4=0



We calculate terms in parentheses: -(4(x-4)+44), so:

4(x-4)+44

We multiply parentheses

4x-16+44

We add all the numbers together, and all the variables

4x+28

Back to the equation:

-(4x+28)



We add all the numbers together, and all the variables

12x-(4x+28)-12=0

We get rid of parentheses

12x-4x-28-12=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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